How does Electromagnetic Radiation work?
October 18, 2019
ABOUT THE AUTHOR
Sabin Mathew, IIT Delhi postgraduate in mechanical engineering. Founder of Lesics Engineers Pvt Ltd & 'LESICS' YouTube channel. He provide quality engineering education on his YouTube channel. And 'LESICS' covers a huge variety of engineering topics. Sabin is a very passionate about understanding the physics behind complex technologies and explaining them in simple words. To know more about the author check this link
In the modern world, we humans are completely surrounded by electromagnetic radiation.
Have you ever thought of the physics behind these travelling electromagnetic waves?
Hertz’s experiment that proved the Maxwell's theory of electromagnetic radiation
The great scientist Heinrich Hertz was the first man to transmit and detect electromagnetic waves.
Inorder to generate Electromagnetic waves, a setup consisting of an induction coil, a capacitor, batteries etc was used. The resulting setup was used to generate high frequency electric current pulses in two metal wire, separated by a distance of 7.5 mm. This whole setup acted as transmitter. When high voltage is applied at the two ends of the separation, a spark was generated.
This spark resulted in the radiation of electromagnetic waves. Those electromagnetic waves traveled through the air and created a spark in a metal coil located over a meter away (Fig:1). If you had placed an LED in that gap, the bulb would have glowed. This was a clear case of electromagnetic wave propagation and detection.
Fig:1 The spark resulted in the radiation of electromagnetic waves and they traveled through the air and created a spark in a metal coil located over a meter away
However, before Hertz, the brilliant mathematician, James Clerk Maxwell, had already laid out
the foundations for electromagnetic radiation by formulating four mathematical equations.
Δ . D = ρv
Δ . B = 0
Δ × E = - ∂B / ∂t
Δ × H = ∂D / ∂t + J
However, these equations, and the Hertz experiment, raised a question: How do
electromagnetic fields detach themselves from wires and propagate through a space? More
specifically what we need is a travelling electromagnetic wave and not a fluctuating one. Let’s
explore this logically.
How does an accelerating charge radiate electromagnetic radiation?
Consider an electric charge, which is moving at a constant speed. The electric field around it is
shown (Fig:2A)& (Fig:2B). Now imagine, for a fraction of a second it accelerates, after that it continues its uniform
motion at a higher speed. What we need to understand is the effect of this acceleration on
the electric field.
Fig:2A The electric field lines when charge is at rest
Fig:2B The electric field lines when charge is moving with constant velocity
The interesting thing is that the information does not travel at an infinite speed, instead it travels
at the speed of light. Similarly, the information about the sudden variation of velocity of the
charge does not get conveyed to the whole electric field region. The field near it knows about it,
but the field far away still has no idea that the charge has accelerated, and it is still in the old
state (Fig:3A). Let’s separate out these regions with the help of two circles (Fig:3B). Since the electric field cannot break, the field between these distances must transition. This transition field is known as a kink (Fig:3C). The kink moves or radiates outwards at the speed of light. We can say here that the acceleration of the charge has caused an electromagnetic disturbance, or electromagnetic radiation.
Fig:3A The electric field lines when charge is accelerated,this information about the sudden variation
of velocity does not get conveyed to the whole electric field region
Fig:3B The old field and new field are separated here with the help of two circles
Fig:3C Since the electric field cannot break, the field between these
distances must transition. This transition field is known as a kink and it radiates outwards at the speed of light
How does an oscillating dipole radiate?
Based on this understanding we will be able to understand the most important experiment in the
field of antenna technology, the oscillating electric dipole. The interesting fact about this simple
oscillating dipole is that it produces electromagnetic radiation in a perfectly sinusoidal manner.
Let’s see how it is achieved. Before getting into the electromagnetics let’s understand how
velocity and acceleration vary in this simple case. It is clear that at both ends the velocities
should be zero, and in the middle the velocity should be at the maximum. This means that this is
a case of continuous acceleration and deceleration. The electric field pattern is drawn here (Fig:4A)
when the chargers are far apart, and when the velocity is zero. In order to have a better
understanding, let’s examine one of the electric field lines (Fig:4B).
Fig:4A The electric field lines of an electric dipole are extended
from the positive to the negative charge
at the speed of light
Fig:4B At t=0, the electric field line
Let’s observe the electric field line at T/8. You can see that the electric field line is deformed as shown in Fig:5. The reason for this deformation is simple, this time period is the region with the highest
acceleration. As we saw earlier, accelerating or decelerating charges cause kinks in the electric field. In short, the old electric field does not get adjusted to the new field very well.
Fig:5 At t=T/8, the expected shape of electric field line and the actual shape of the electric field line
This deformation is continuous since there is continuous acceleration in the charge. When 2 charges
meet at the central point, the deformed line also meets there (Fig:6A), after that it detaches and radiates. This radiation travels at the speed of light. If you plot an electric field intensity variation, with respect to length, you can see that the radiation we have produced is perfectly sinusoidal in
nature (Fig:6B). Please note that this varying electric field will automatically generate a varying magnetic field, perpendicular to it.
Fig:6A
At t=T/4, the ends of electric field meets at a single point
and the separation and propagation happens
Fig:6B Electromagnetic radiation in an electric dipole
How does an antenna radiate?
Now let's have a look at how this applies to an antenna. A time varying voltage is applied to the
metal wire as shown (Fig:7). Due to the effect of the voltage, the electrons will be displaced from right
to left and create positive and negative charges. With the continuous variation of voltage, the
positive and negative charges will shuttle back and forth in the wire. This simple arrangement is
known as a dipole antenna. The dipole antenna produces the same radiation as we saw in the
previous section. In this case, the antenna works as a transmitter. The frequency of the
transmitted signal will be the same as the frequency of the applied voltage signal.
Fig:7 With the continuous variation of voltage, the positive and negative charges will shuttle back and forth in the wire and the dipole antenna produces the radiation
How does an antenna receive signals?
The same antenna can act as a receiver if the operation of the antenna is reversed. When
propagating electromagnetic waves strike the antenna, the oscillating fields of waves create
positive and negative charges at the ends of the antenna. The varying charge accumulation
means a varying voltage signal is produced at the center of the antenna. This voltage signal is
the output when the antenna works as a receiver (Fig:8).
Fig:8 Antenna can work as a receiver if a propagating electromagnetic field hits it
Antenna design criterion for proper transmission or reception:
1. Antenna size
We can note here that for perfect transmission or reception the length of the antenna should be
half of the wavelength (Fig:9). This is the first antenna design criterion for proper reception or
transmission.
Fig:9 For perfect transmission or reception the length of the antenna should be half of the wavelength
2. Impedance matching : why it is Important ?
The second most important design criterion is a term called impedance matching. Perfect
impedance matching will make sure that the waves are radiated in the most efficient way. When
an alternating current passes through a circuit, it faces opposition from the combined effects of
resistance, inductance and capacitance. This combined effect is known as impedance.
According to the maximum power-transfer theorem, to transfer the maximum amount of power
the load impedance should match with the source impedance as shown in Fig:10A.
For further understanding, let's take an example of a circuit containing an alternator as a source, and a motor, bulb etc. as a load. In this setup, to achieve maximum power transfer from alternator to the load, the impedance of the load, must match with the impedance of the alternator (Fig:10B).
Fig:10A To achieve maximum power transfer in any electric circuit, the load impedance should match with the source impedance
Fig:10B To achieve maximum power transfer in this circuit, the impedance of the load, must match with the impedance of the alternator
Impedance matching in the antenna
A similar impedance balance is required in the case of an antenna system. Since an antenna
works on high frequency signals, the impedance of the transmission lines also becomes
important (Fig:11A). Hence to achieve maximum power, the impedance of an antenna should match to
the impedance of the source and transmission line as well. If the impedances do not match,
some portion of the power would be reflected back to the source instead of radiating outwards
from the antenna (Fig:11B).
Fig:11A In antenna system, to achieve maximum power, the impedance of an antenna should match to the impedance of the source and transmission line as well
Fig:11B If the impedances do not match in antenna, some portion of the power would be reflected back to the source instead of radiating outwards from the antenna
Impedance matching in a parabolic antenna using a feedhorn:
A free space has an impedance value of 377 Ohm. In a parabolic antenna, a waveguide is used
as a transmission line, which has a different impedance value from the free space. That's why a feedhorn is also included in a parabolic antenna(Fig:12). This way the impedance of the waveguide is
matched with the impedance of the free space so that the EM waves can be received properly.
Fig:12 In a parabolic antenna, a feedhorn is used to match the impedance of the waveguide to the impedance of free space (377 ohm)
ABOUT THE AUTHOR
PRERNA GUPTA
A post graduate in Control and Instrumentation. Currently she is working at Lesics engineers Pvt.Ltd as a Team lead for Visual Education. Her areas of interest are Telecommunication, Semiconductor Material and devices, Embedded systems and design. Prerna has done projects such as MOSFET, Optical fiber cable, Routing, GPS System, Modulation, Satellite, Working of Mobile phone, Electromagnetic radiation Etc. To know more about the author check this link